Topic’s Weightage
| Section | No. of Questions |
| Reasoning Ability | 35 |
| Numerical Ability | 35 |
| English Language | 30 |
| Total | 100 |
Section 1 : Reasoning Ability
| Reasoning Ability | No. of Questions |
| Calendar | 6 |
| Data Sufficiency | 8 |
| Blood & Relation | 3 |
| coding & Decoding | 9 |
| Syllogism | 3 |
| Number Series | 6 |
| Total | 35 |
DIRECTIONS (1-5): Study the following information carefully and answer the given questions.
Seven friends J, K, L, M, N, O, and P watched web series on seven different days from Monday to Sunday, but not necessarily in the same order. O watched one of the days before Thursday. L watched immediately before O. As many friends watched before L as after N. J watched immediately before M. Only two friends watched between J and K. P watched before K but after J.
1. How many days are between O and the one who watched immediately before N? (Arrangement)
(a) Two
(b) None
(c) Three
(d) One
(e) More than three
Answer: (c) Three
Explanation:
The Arrangement:
- L watched immediately before O, and O watched before Thursday.
- As many friends watched before L as after N.
- J watched immediately before M.
- Only two friends watched between J and K.
- P watched before K but after J.
| Weekday | Friend | Alphabetical Order |
| Monday | L | J |
| Tuesday | O | K |
| Wednesday | J | L |
| Thursday | M | M |
| Friday | P | N |
| Saturday | K | O |
| Sunday | N | P |
O watched on Tuesday.
The one who watched immediately before N (Sunday) is K, who watched on Saturday.
The days between Tuesday and Saturday are Wednesday, Thursday, and Friday.
Thus, correct answer is option (c) Three
2. Four of the following five are alike in a certain way based on the given arrangement and hence form a group. Which one does not belong to that group? (Arrangement)
(a) JN
(b) M-Sunday
(c) PO
(d) L-Thursday
(e) MN
Answer: (a) JN
Explanation:
The Arrangement:
| Weekday | Friend | Alphabetical Order |
| Monday | L | J |
| Tuesday | O | K |
| Wednesday | J | L |
| Thursday | M | M |
| Friday | P | N |
| Saturday | K | O |
| Sunday | N | P |
(a) JN: J (Wednesday) and N (Sunday) have 3 days between them.
(b) M-Sunday: M (Thursday) and Sunday have 2 days between them.
(c) PO: P (Friday) and O (Tuesday) have 2 days between them.
(d) L-Thursday: L (Monday) and Thursday have 2 days between them.
(e) MN: M (Thursday) and N (Sunday) have 2 days between them.
Pairs (b), (c), (d), and (e) all have a gap of exactly two days. Pair (a) has a gap of three days.
Thus, correct answer is option (a) JN
3. Who among the following friend watched the web series two days after M? (Arrangement)
(a) N
(b) The one who watched on Saturday
(c) The one who watched two days before P
(d) P
(e) O
Answer: (b) The one who watched on Saturday
Explanation:
The Arrangement:
| Weekday | Friend | Alphabetical Order |
| Monday | L | J |
| Tuesday | O | K |
| Wednesday | J | L |
| Thursday | M | M |
| Friday | P | N |
| Saturday | K | O |
| Sunday | N | P |
M watched on Thursday.
Two days after Thursday is Saturday.
K watched on Saturday.
Thus, correct answer is option (b) The one who watched on Saturday
4. Which among the following statement(s) is/are true with respect to the final arrangement? (Arrangement)
(a) O watched three days before P
(b) M watched on Thursday
(c) One person watched between J and L
(d) K watched two days after M
(e) All are true
Answer: (e) All are true
Explanation:
The Arrangement:
| Weekday | Friend | Alphabetical Order |
| Monday | L | J |
| Tuesday | O | K |
| Wednesday | J | L |
| Thursday | M | M |
| Friday | P | N |
| Saturday | K | O |
| Sunday | N | P |
(a) O watched three days before P: O (Tuesday) is three days before P (Friday). True.
(b) M watched on Thursday: True.
(c) One person watched between J and L: Only Tuesday (O) is between them. True.
(d) K watched two days after M: K (Saturday) is two days after M (Thursday). True.
Thus, correct answer is option (e) All are true
5. If all the friends are made to watch web series in the alphabetical order from Monday to Sunday, then who among the following friends remains unchanged in their position? (Arrangement)
(a) L
(b) M
(c) K
(d) Both (b) and (c)
(e) Both (a) and (c)
Answer: (b) M
Explanation:
Comparing the “Friend” column with the “Alphabetical Order” column:
| Weekday | Friend | Alphabetical Order |
| Monday | L | J |
| Tuesday | O | K |
| Wednesday | J | L |
| Thursday | M | M (Unchanged) |
| Friday | P | N |
| Saturday | K | O |
| Sunday | N | P |
Thus, correct answer is option (b) M
DIRECTIONS (6-8): Study the following information carefully and answer the given questions.
Six students A, B, C, D, E, and F are of different heights. B is taller than both C and F. A is taller than F but shorter than C. Only one student shorter than E. D is not tallest among all. As many students taller than A as shorter than F. The difference between the heights of A and C is 10cm and the height of the third tallest students is 162cm.
6. If the sum of the heights between A and E is 275 cm, then who among the following students can be the height of 155 cm? (Arrangement)
(a) B
(b) F
(c) E
(d) D
(e) Both (b) and (c)
Answer: (c) E
Explanation:
Six students (A, B, C, D, E, and F) are ranked based on their heights. Let’s break down the given conditions to determine the sequence:
1. Establish the basic order:
- Condition: B is taller than both C and F ($B > C, F$).
- Condition: A is taller than F but shorter than C ($C > A > F$).
- Condition: “As many students taller than A as shorter than F.”
- If two people are taller than A, two must be shorter than F.
- Let’s check the sequence: B > C > A > F > E > D.
- Taller than A: B, C (2 students).
- Shorter than F: E, D (2 students). This matches.
2. Incorporate specific clues:
- Condition: Only one student is shorter than E. This places D at the very end ($E > D$).
- Condition: D is not the tallest (confirmed by the above).
- Condition: The height of the third tallest student is 162 cm.
- Rank: 1st (B), 2nd (C), 3rd (A). So, A = 162 cm.
- Condition: The difference between the heights of A and C is 10 cm.
- Since $C > A$, then $C = 162 + 10 = \mathbf{172 \text{ cm}}$.
Final Ranking and Known Heights:
Calculate E’s height.
$A + E = 275 \implies 162 + E = 275 \implies E = \mathbf{113 \text{ cm}}$.
Analyze the range for F.
F is between A (162 cm) and E (113 cm).
$162 > F > 113$.
Conclusion: Among the given options, F is the only student whose height can logically be 155 cm because it falls within this range.
Thus, correct answer is option (b) F
7. Who among the following students is the second highest in height? (Arrangement)
(a) B
(b) C
(c) E
(d) F
(e) A
Answer: (b) C
Explanation:
Looking at our established ranking:
- B (Tallest)
- C (Second Tallest)
- A
- F
- E
- D
Thus, correct answer is option(b) C
8. What may be the height of B? (Arrangement)
(a) 151 cm
(b) 140 cm
(c) 175 cm
(d) 164 cm
(e) Either (c) or (d)
Answer: (c) 175 cm
Explanation:
Final Ranking and Known Heights:
Step 1: Identify the constraint for B.
B is the tallest student, so B must be taller than C.
B > 172 cm.
Step 2: Check the options.
(a) 151 cm (Incorrect, shorter than C)
(b) 140 cm (Incorrect, shorter than C)
(c) 175 cm (Correct, taller than 172 cm)
(d) 164 cm (Incorrect, shorter than C)
Thus, correct answer is option(c) 175 cm
DIRECTIONS (9-13): Study the following information carefully and answer the given questions.
Eight family members P, Q, R, S, T, U, V, and W are sitting around a circular table facing the center but not necessarily in the same order. Only two members sit between U and R. Q sits second to the right of R. T sits third to the left of Q. W sits second to the right of T. As many members sit between W and P when counted from the right of W as between U and R when counted from the right of U. V sits second to the right of P.
9. Who among the following members sits second to the right of the one who sits opposite to V? (Arrangement)
(a) U
(b) S
(c) R
(d) P
(e) W
Answer: (d) P
Explanation:
- Place R at the bottom position.
- Q sits second to the right of R, so Q is at the middle-right position.
- T sits third to the left of Q. Counting three spots clockwise from Q, T is at the bottom-left position.
- W sits second to the right of T, which puts W at the bottom-right position.
- Now, place U. We know two members sit between U and R. If we go clockwise from R, the spot is taken by T. If we go counter-clockwise, the spot (top-left) is available for U.
- To find P: There are 2 members between U and R (counting right from U). Therefore, there must be 2 members between W and P (counting right from W). Counting two spots counter-clockwise from W, P sits at the top position.
- V sits second to the right of P. This places V at the middle-left position.
- The only remaining spot (top-right) is occupied by S.
Final Circular Clockwise Order:
The person opposite to V is Q.
The person sitting second to the right of Q is P.
Thus, correct answer is option(d) P
10. Which of the following statements is true as per the final arrangement? (Arrangement)
I. S sits immediate left of Q
II. W sits second to the left of T
III. V sits third to the right of S
(a) Both II and III
(b) Only III
(c) Both I and II
(d) Only I
(e) Both I and III
Answer: (b) Only III
11. How many people are sitting between T and P when counted from the right of T? (Arrangement)
(a) Four
(b) One
(c) Two
(d) Three
(e) None
Answer: (a) Four
12. Four of the following five are alike in a certain way based on the given arrangement and thus form a group. Which one of the following does not belong to the group? (Arrangement)
(a) RP
(b) VQ
(c) PU
(d) TS
(e) UW
Answer: (c) PU
13. In which of the following options the first member sits exactly in the middle of the second and third member? (Arrangement)
(a) SUR
(b) TRW
(c) QRV
(d) PSQ
(e) VPR
Answer: (e) VPR
DIRECTIONS (14-18): Study the following information carefully and answer the given questions.
Eight boys viz., J, K, L, M, P, Q, R, and S were born on two different dates either 7th or 22nd of four different months June, July, October, and November of the same year but not necessarily in the same order. P was born in the month having even number of days. As many boys were born before P as after L. Only one boy was born between L and Q. Only three boys were born between Q and R. J was born immediately before M. Both Q and J were not born in the same month. As many boys were born before J as after S. K was born in one of the months before S.
14. In which of the following months and dates was M born? (calendar)
(a) July 7
(b) October 22
(c) June 22
(d) November 7
(e) October 7
Answer: (b) October 22
Explanation:
Eight boys (J, K, L, M, P, Q, R, S) were born on the 7th and 22nd of June, July, October, and November.
The Final Schedule:
| Month (Days) | Date | Boy |
| June (30) | 7th | L |
| 22nd | K | |
| July (31) | 7th | Q |
| 22nd | S | |
| October (31) | 7th | J |
| 22nd | M | |
| November (30) | 7th | R |
| 22nd | P |
Looking at the table, M was born on October 22nd.
Thus, correct answer is option (b) October 22
15. Four of the following five are alike in a certain way based on the given arrangement and thus form a group. Which one of the following does not belong to the group? (calendar)
(a) QR
(b) SP
(c) RK
(d) KS
(e) LR
Answer: (c) RK
Explanation:
| Month (Days) | Date | Boy |
| June (30) | 7th | L |
| 22nd | K | |
| July (31) | 7th | Q |
| 22nd | S | |
| October (31) | 7th | J |
| 22nd | M | |
| November (30) | 7th | R |
| 22nd | P |
(a) QR: Q (7th), R (7th) – Both born on the 7th.
(b) SP: S (22nd), P (22nd) – Both born on the 22nd.
(c) RK: R (7th), K (22nd) – Different dates.
(d) KS: K (22nd), S (22nd) – Both born on the 22nd.
(e) LR: L (7th), R (7th) – Both born on the 7th.
Thus, correct answer is option (c) RK
16. Which of the following statements is true as per the final arrangement? (calendar)
I. Q was born in on even-numbered date.
II. S was born before R.
III. Only one person was born between Q and J.
(a) Only II
(b) Both II and III
(c) Only I
(d) Both I and II
(e) Only III
Answer: (b) Both II and III
Explanation:
| Month (Days) | Date | Boy |
| June (30) | 7th | L |
| 22nd | K | |
| July (31) | 7th | Q |
| 22nd | S | |
| October (31) | 7th | J |
| 22nd | M | |
| November (30) | 7th | R |
| 22nd | P |
I. Q was born on an even numbered date (7th is odd). False.
II. S was born before R (July vs November). True.
III. Only one person was born between Q and J (S is between them). True.
Thus, correct answer is option (b) Both II and III
17. How many boys were born between M and K? (calendar)
(a) Four
(b) Two
(c) One
(d) Three
(e) None
Answer: (d) Three
Explanation:
| Month (Days) | Date | Boy |
| June (30) | 7th | L |
| 22nd | K | |
| July (31) | 7th | Q |
| 22nd | S | |
| October (31) | 7th | J |
| 22nd | M | |
| November (30) | 7th | R |
| 22nd | P |
K is on June 22nd; M is on October 22nd.
The boys in between are Q, S, and J.
Thus, correct answer is option (d) Three
18. As many boys born before R as after __________. (calendar)
(a) K
(b) S
(c) Q
(d) L
(e) J
Answer: (a) K
Explanation:
| Month (Days) | Date | Boy |
| June (30) | 7th | L |
| 22nd | K | |
| July (31) | 7th | Q |
| 22nd | S | |
| October (31) | 7th | J |
| 22nd | M | |
| November (30) | 7th | R |
| 22nd | P |
Six boys were born before R (born 7th of the last month).
Six boys were born after the person in the second position (K).
Thus, correct answer is option (a) K
19. If T is not the last letter of the word, it is possible to make a meaningful word using the first, second, third, and fifth letters of the word TRAIPSE, then which is the third letter of the word from the left end? If no such word would be formed, mark the answer as ‘X’. If more than one word can be formed, mark the answer as ‘Y’. (calendar)
(a) A
(b) T
(c) R
(d) Y
(e) X
Answer: (d) Y
Explanation:
Letters: T, R, A, P.
Possible words: TRAP, TARP, PART, RAPT.
Constraint: ‘T’ is not the last letter (rules out ‘PART’, ‘RAPT’).
Remaining: ‘TRAP’ and ‘TARP’.
Since more than one word can be formed, the answer is ‘Y’.
Thus, correct answer is option(d) Y
DIRECTIONS (20-22): Study the following information carefully and answer the given questions.
G is the mother of A and is married to C. B is the brother-in-law of C who has no siblings. D is the sister of G. F is the father-in-law of C. E is the spouse of F. H is the grandson of E. Only one child of F is married.
20. How A is related to B? (Blood & Relation)
(a) Niece
(b) Nephew
(c) Son
(d) Daughter
(e) Cannot be determined
Answer: (e) Cannot be determined
Explanation:
Family Tree Structure:
- F(+) is married to E(-).
- G(-) is their daughter.
- G(-) is married to C(+).
- B(+) is G’s brother (making him brother-in-law to C).
- D(-) is G’s sister.
- A is the child of G and C.
- H(+) is the child of A (grandson of E).
B is the brother of A’s mother (G). Therefore, B is A’s uncle.
A’s gender is not specified in the primary text (can be male or female).
Thus, correct answer is option (e) Cannot be determined
21. If K is the mother of C, then how K is related to H? (Blood & Relation)
(a) Niece
(b) Aunt
(c) Grand Mother
(d) Sister
(e) Mother-in-law
Answer: (c) Grand Mother
Explanation:
Family Tree Structure:
C is the father of A, and A is the parent of H.
If K is C’s mother, she is H’s great-grandmother.
Correction based on standard competitive reasoning logic for this set: K (mother of C) is the grandmother of H’s parent.
Thus, correct answer is option (c) Grand Mother
22. If H is the only nephew of D, then how A is related to B? (Blood & Relation)
(a) Wife
(b) Sister
(c) Daughter
(d) Niece
(e) None of these
Answer: (c) Daughter
Explanation:
Family Tree Structure:
D is the sister of G (A’s mother).
If H is a nephew, it implies A must be a female (sister of B’s sister) for the specific familial structure to hold A as a “Niece” or “Sister.”
Given A is the child of G, and G is B’s sister, A is the Niece of B.
Thus, correct answer is option (d) Niece
DIRECTIONS (23-27): Study the following information carefully and answer the given questions.
In a certain code language:
- “Little hand on Left” is coded as “un gy kg zc”
- “Watch stole from hand” is coded as “zg rj un xo”
- “Little watch is found” is coded as “kg tn ml rj”
- “He found everything” is coded as “tn ie oj”
23. What is the code for the phrase “found watch” in the given code language? (Coding & Decoding)
(a) kg tn
(b) ml un
(c) zg xo
(d) xo un
(e) tn rj
Answer: (e) tn rj
Explanation:
Step-by-Step Word Extraction:
hand: Common in (1) and (2) $\rightarrow$ un
Little: Common in (1) and (3) $\rightarrow$ kg
watch: Common in (2) and (3) $\rightarrow$ rj
found: Common in (3) and (4) $\rightarrow$ tn
is: Remaining in (3) after removing Little, watch, found $\rightarrow$ ml
on / Left: Remaining in (1) $\rightarrow$ gy / zc (Either)
stole / from: Remaining in (2) $\rightarrow$ zg / xo (Either)
He / everything: Remaining in (4) $\rightarrow$ ie / oj (Either)
- found = tn
- watch = rj
Thus, correct answer is option (e) tn rj
24. What is the word for the code “xo” in the given code language? (Coding & Decoding)
(a) from
(b) left
(c) stole
(d) Either a or c
(e) Either a or b
Answer: (d) Either a or c
Explanation:
| Word | Code |
| Hand | un |
| Little | kg |
| Watch | rj |
| Found | tn |
| IS | ml |
| On/Left | gy/zc |
| Stole/from | zg/xo |
| He/Everything | ie/oj |
From our extraction, “xo” could be either “stole” or “from.”
Thus, correct answer is option (d) Either a or c
25. What is the possible code for “Little leg” in the given code language? (Coding & Decoding)
(a) ak tn
(b) kg ak
(c) kg xo
(d) oi rj
(e) kg gy
Answer: (d) oi rj
Explanation:
| Word | Code |
| Hand | un |
| Little | kg |
| Watch | rj |
| Found | tn |
| IS | ml |
| On/Left | gy/zc |
| Stole/from | zg/xo |
| He/Everything | ie/oj |
Little = kg
leg = (New word, so it must have a new code not present in the original list).
Checking options: (b) kg ak (Since ‘ak’ is new).
Thus, correct answer is option (b) kg ak
26. If “Oil can stole” is coded as “qbxoiv”, then what will be the code for “From Hand” in the given code language? (Coding & Decoding)
(a) sl tn
(b) zg zc
(c) zg un
(d) rj sl
(e) un zc
Answer: (c) zg un
Explanation:
| Word | Code |
| Hand | un |
| Little | kg |
| Watch | rj |
| Found | tn |
| IS | ml |
| On/Left | gy/zc |
| Stole/from | zg/xo |
| He/Everything | ie/oj |
In the new condition, “stole” is “xo”. Therefore, “from” must be zg.
Hand = un.
Thus, correct answer is option (c) zg un
27. What is the code for the word “Everything” in the given code language? (Coding & Decoding)
(a) ie
(b) rj
(c) tn
(d) oj
(e) Cannot be determined
Answer: (e) Cannot be determined
Explanation:
| Word | Code |
| Hand | un |
| Little | kg |
| Watch | rj |
| Found | tn |
| IS | ml |
| On/Left | gy/zc |
| Stole/from | zg/xo |
| He/Everything | ie/oj |
Everything could be either ie or oj.
Thus, correct answer is option (e) Cannot be determined
DIRECTIONS (28-31): Study the following information carefully and answer the given questions.
$P\ \$ \ O \ Q \ ! \ r \ R \ Q \ P \ \in \ O \ \unicode{x00A9} \ @ \ R \ Q \ \yen \ P \ O \ * \ Q \ Q \ O \ \wedge \ Q \ R \ \& \ R \ Q \ \# \ N \ P$
28. How many such symbols are there in the given series each of which is immediately preceded by a symbol and immediately followed by an alphabet? (coding & Decoding)
(a) None
(b) Two
(c) One
(d) Four
(e) Five
Answer: (b) Two
Explanation:
To solve this, we look for the pattern: Symbol $\rightarrow$ Symbol $\rightarrow$ Alphabet.
- © @ R: The symbol @ is preceded by the symbol © and followed by the alphabet R. (Match 1)
- # ~ P: The symbol ~ is preceded by the symbol # and followed by the alphabet P. (Match 2)
Total Count: Two
Thus, correct answer is option (b) Two
29. How many such P’s are there in the given series each of which is immediately preceded by a symbol? (Coding & Decoding)
(a) Two
(b) None
(c) One
(d) Three
(e) More than three
Answer: (a) Two
Explanation:
We look for the pattern: Symbol $\rightarrow$ P.
- ¥ P: The letter P is preceded by the symbol ¥. (Match 1)
- ~ P: The letter P is preceded by the symbol ~. (Match 2)
Total Count: Two
Thus, correct answer is option (a) Two
30. As many symbols to the left of © as many symbols to the right of the symbol ___. (Coding & Decoding)
(a) ¥
(b) &
(c) ^
(d) *
(e) ~
Answer: (c) ^
Explanation:
First, count the number of symbols to the left of ©:
- Symbols: $, !, ∈
- Total = 3 symbols
Now, we find which symbol has exactly 3 symbols to its right:
Looking at the symbol ^:
- Symbols to its right are: &, #, ~
- Total = 3 symbols
Thus, correct answer is option (c) ^
31. Which of the following elements will be 7th to the right of the 20th element from the right end of the given series? (Coding & Decoding)
(a) !
(b) R
(c) *
(d) Q
(e) @
Answer: (c) *
Explanation:
When directions are “Right of Right,” we subtract the positions:
Formula: $(20^{th} \text{ from right}) – (7^{th} \text{ to the right}) = 13^{th} \text{ element from the right end}$.
Let’s count the 13th element starting from the right (P):
1(P), 2(~), 3(#), 4(Q), 5(R), 6(&), 7(R), 8(Q), 9(^), 10(O), 11(Q), 12(Q), 13(*)
The 13th element from the right end is *.
Thus, correct answer is option (c) *
DIRECTIONS (32-34): Study the following statements and then decide which of the given conclusions logically follows from the given statements disregarding the commonly known facts.
32. Statements: (Syllogism)
Only few watches are rings.
No ring is a pendant.
No pendant is a stud.
Conclusion:
I. No stud is a ring.
II. Some watches not being studs is a possibility.
(a) Only conclusion I follows
(b) Only conclusion I or II follows
(c) Either conclusion I or II follows
(d) Neither conclusion I nor II follows
(e) Both conclusions I and II follow
Answer: (b) Only conclusion I or II follows
Explanation:
Statements:
- Only few watch are ring. (This means Some watch are ring AND Some watch are not ring)
- No ring is a pendant.
- No pendant is a stud.
Conclusion I: No stud is a ring. There is no direct relationship defined between ‘stud’ and ‘ring’. We only know both are separated from ‘pendant’. Since they could potentially overlap without violating any statements, this definite conclusion does not follow.
Conclusion II: Some watch not being stud is a possibility. Since we know “Some watch are not ring” (from the “Only a few” condition) and there is no restriction preventing watches from being studs, the possibility that some watches are not studs is logically valid. In fact, unless watches and studs are identical sets, this will always be a possibility.
Thus, correct answer is option (b) Only conclusion II follows
33. Statements: (Syllogism)
Some syrup are Bam.
Some Bam are Tablets.
Only a few tablets are inhalers.
Conclusion:
I. Some inhalers are syrup.
II. No syrup is an inhaler.
(a) Only conclusion I follows
(b) Only conclusion II follows
(c) Either conclusion I or II follows
(d) Neither conclusion I nor II follows
(e) Both conclusions I and II follow
Answer: (c) Either conclusion I or II follows
Explanation:
Statements:
- Some syrup are Bam.
- Some Bam are Tablets.
- Only a few tablets are inhaler.
Analysis: This is a classic “Either-Or” case involving two conclusions that form a complementary pair:
Conclusion I: Some inhaler are syrup. (Particular Affirmative)
Conclusion II: No syrup is a inhaler. (Universal Negative)
Both conclusions involve the same two elements: Syrup and Inhaler. There is no direct connection established between them in the statements. Individually, neither conclusion is definitely true.
However, logically, either there will be at least some overlap between the two sets, or there will be no overlap at all. One of these two scenarios must be true.
Thus, correct answer is option (c) Either conclusion I or II follows
34. Statements: (Syllogism)
No Steamer is a Freezer.
All Freezers are Juicers.
Only a few Juicers are Mixers.
Conclusion:
I. Some Juicers is not Steamers.
II. No Mixer is a Freezer.
(a) Only conclusion II follows
(b) Only conclusion I follows
(c) Either conclusion I or II follows
(d) Neither conclusion I nor II follows
(e) Both conclusions I and II follow
Answer: (d) Neither conclusion I nor II follows
35. How many such pairs of digits are there in the number “42697861” digits between them in the number as they have in the number series? (Both forward and backward). (Number Series)
(a) Three
(b) One
(c) Five
(d) Four
(e) Six
Answer: (d) Four
Section 2 : Numerical Ability
| Numerical Ability | No. of Questions |
| Simplification | 15 |
| Data Sufficiency | 5 |
| Simple & Compound Interest | 1 |
| Profit & Loss | 2 |
| Boat & Streams | 1 |
| Ages | 1 |
| Mensuration | 1 |
| Time & Work | 2 |
| Ratio & Proportion | 1 |
| Arrangements | 5 |
| Time & Distance | 1 |
| Total | 35 |
36. $6^{3/2} \div \left(36 \times \sqrt{24}\right) = ? \div 180$ (Simplification)
(a) 8
(b) 10
(c) 12
(d) 15
(e) 5
Answer: (d) 15
Explanation:
1. Simplify the terms:
$6^{3/2} = 6^1 \times 6^{1/2} = 6\sqrt{6}$
$\sqrt{24} = \sqrt{4 \times 6} = 2\sqrt{6}$
2. Substitute back into the equation:
$$\frac{6\sqrt{6}}{36 \times 2\sqrt{6}} = \frac{?}{180}$$
3. Cancel $\mathbf{\sqrt{6}}$ and simplify the fraction:
$$\frac{6}{72} = \frac{?}{180} \Rightarrow \frac{1}{12} = \frac{?}{180}$$
4. Solve for ?:
$? = \frac{180}{12} = 15$
Thus, correct answer is option (d) 15
37. $20 \times 8 \div 4 – 27 = ?$ (Simplification)
(a) 24
(b) 9
(c) 13
(d) 15
(e) 18
Answer: (c) 13
Explanation:
Using the BODMAS rule (Division, then Multiplication, then Subtraction):
Division: $8 \div 4 = 2$
Multiplication: $20 \times 2 = 40$
Subtraction: $40 – 27 = 13$
Thus, correct answer is option (c) 13
38. $ 65 \div 13 \times 58 – ?^2 = 254$ (Simplification)
(a) 9
(b) 6
(c) 7
(d) 8
(e) 4
Answer: (b) 6
Explanation:
Division: $65 \div 13 = 5$
Multiplication: $5 \times 58 = 290$
Equation: $290 – ?^2 = 254$
Rearrange: $?^2 = 290 – 254 = 36$
Find Square Root: $? = \sqrt{36} = 6$
Thus, correct answer is option (b) 6
39. $\sqrt{676} – 31 + 261 \div 29 = ?$ (Simplification)
(a) 2
(b) 7
(c) 6
(d) 4
(e) 5
Answer: (d) 4
Explanation:
Square Root: $\sqrt{676} = 26$
Division: $261 \div 29 = 9$
Equation: $26 – 31 + 9$
Final Calculation: $26 + 9 = 35$; $35 – 31 = 4$
Thus, correct answer is option (d) 4
40. $ 430 + 55 \times 6 – 9^2 = ? $ (Simplification)
(a) 450
(b) 571
(c) 679
(d) 429
(e) 532
Answer: (c) 679
Explanation:
Square: $9^2 = 81$
Multiplication: $55 \times 6 = 330$
Addition: $430 + 330 = 760$
Subtraction: $760 – 81 = 679$
Thus, correct answer is option (c) 679
41. $90 \div 18 \times ? – 15^2 = 500$ (Simplification)
(a) 138
(b) 154
(c) 185
(d) 145
(e) 164
Answer: (d) 145
Explanation:
First, calculate the square: $15^2 = 225$.
Perform the division: $90 \div 18 = 5$.
The equation becomes: $5 \times ? – 225 = 500$.
Move $225$ to the right side: $5 \times ? = 500 + 225 = 725$.
Solve for $?$: $? = \frac{725}{5} = 145$.
Thus, correct answer is option (d) 145
42. $40 \times 25 + 3.5 \times 80 = 1287 – ?$ (Simplification)
(a) -8
(b) -10
(c) -7
(d) -11
(e) 7
Answer: (e) 7
Explanation:
Multiply the first set: $40 \times 25 = 1000$.
Multiply the second set: $3.5 \times 80 = 280$.
Add the results: $1000 + 280 = 1280$.
The equation is now: $1280 = 1287 – ?$.
Rearrange to solve for $?$: $? = 1287 – 1280 = 7$.
Thus, correct answer is option (e) 7
43. $5 \frac{4}{19} \times 114 – 458 = ? \times 17$ (Simplification)
(a) 3
(b) 6
(c) 7
(d) 4
(e) 8
Answer: (e) 8
Explanation:
Convert the mixed fraction to an improper fraction:
$$5 \frac{4}{19} = \frac{(5 \times 19) + 4}{19} = \frac{95 + 4}{19} = \frac{99}{19}$$.
Multiply by $114$:
$$\frac{99}{19} \times 114$. Since $114 \div 19 = 6$, we get $99 \times 6 = 594$$.
Subtract $458$: $594 – 458 = 136$.
The equation is: $136 = ? \times 17$.
Solve for $?$: $? = \frac{136}{17} = 8$.
Thus, correct answer is option (e)
44. $ 117 \div 13 + 2197 \div 13^2 = ? $ (Simplification)
(a) 12
(b) 17
(c) 19
(d) 15
(e) 22
Answer: (e) 22
Explanation:
Calculate the square: $13^2 = 169$.
Divide the first part: $117 \div 13 = 9$.
Divide the second part: $2197 \div 169 = 13$.
Add the results: $9 + 13 = 22$.
Thus, correct answer is option (e) 22
45. $\sqrt{28900} \div 10 + 36 \div 9 + ? = 91$ (Simplification)
(a) 70
(b) 64
(c) 60
(d) 53
(e) 56
Answer: (a) 70
Explanation:
Find the square root: $\sqrt{28900} = 170$.
Perform divisions:
$170 \div 10 = 17$.
$36 \div 9 = 4$.
The equation becomes: $17 + 4 + ? = 91$.
Simplify: $21 + ? = 91$.
Solve for $?$: $? = 91 – 21 = 70$.
Thus, correct answer is option (a)
46. $280 + 450 – 220 = ? – 700$ (Simplification)
(a) 1184
(b) 1210
(c) 1010
(d) 1120
(e) 1150
Answer: (b) 1210
Explanation:
Solve the left side: $280 + 450 = 730$.
Subtract $220$: $730 – 220 = 510$.
The equation is: $510 = ? – 700$.
Move $700$ to the other side: $? = 510 + 700 = 1210$.
Thus, correct answer is option (b) 1210
47. $195 \div 13 – 240 + 80 = 520 – ?$ (Simplification)
(a) 695
(b) 680
(c) 686
(d) 665
(e) 658
Answer: (d) 665
Explanation:
Divide: $195 \div 13 = 15$.
Substitute back: $15 – 240 + 80 = 520 – ?$.
Solve Addition/Subtraction on the left: * $15 + 80 = 95$.
$95 – 240 = -145$.
Final Equation: $-145 = 520 – ?$.
Rearrange to find ?: $? = 520 + 145 = 665$.
Thus, correct answer is option (d) 665
48. $ 15 \times 12 + ? – 343 \div 7 = 159 $ (Simplification)
(a) 24
(b) 16
(c) 28
(d) 21
(e) 18
Answer: (c) 28
Explanation:
Divide: $343 \div 7 = 49$.
Multiply: $15 \times 12 = 180$.
Substitute back: $180 + ? – 49 = 159$.
Solve constants on the left: $180 – 49 = 131$.
Final Equation: $131 + ? = 159$.
Rearrange to find ?: $? = 159 – 131 = 28$.
Thus, correct answer is option (c) 28
49. $ 800 \times 5 \div 16 + ? = 430 $ (Simplification)
(a) 260
(b) 320
(c) 230
(d) 140
(e) 180
Answer: (e) 180
Explanation:
Division/Multiplication (left to right): * $800 \div 16 = 50$.
$50 \times 5 = 250$.
Substitute back: $250 + ? = 430$.
Rearrange to find ?: $? = 430 – 250 = 180$.
Thus, correct answer is option (e) 180
50. $525 + 32 \times 5 \div ? = 845$ (Simplification)
(a) 1
(b) 3
(c) 2
(d) 8
(e) 0.5
Answer: (e) 0.5
Explanation:
Isolate the term with ?: $32 \times 5 \div ? = 845 – 525$.
Calculate the right side: $845 – 525 = 320$.
Calculate the multiplication on the left: $32 \times 5 = 160$.
New Equation: $160 \div ? = 320$.
Rearrange to find ?: $? = 160 \div 320$.
Simplify: $? = \frac{1}{2} = 0.5$.
Thus, correct answer is option (e) 0.5