Section 2 : Numerical Ability
| Numerical Ability | No. of Questions |
| Simplification | 15 |
| Data Sufficiency | 5 |
| Simple & Compound Interest | 1 |
| Profit & Loss | 2 |
| Boat & Streams | 1 |
| Ages | 1 |
| Mensuration | 1 |
| Time & Work | 2 |
| Ratio & Proportion | 1 |
| Arrangements | 5 |
| Time & Distance | 1 |
| Total | 35 |
DIRECTIONS (Qs. 51–55): Read the following information carefully and answer the questions given below.
The given table chart shows the number of mobiles sold in 2021 and 2022 by four different shops namely P, Q, R, and S.
| Company | Number of mobiles sold in 2021 | Number of mobiles sold in 2022 |
| P | 540 | 900 |
| Q | 840 | 640 |
| R | 600 | 800 |
| S | 960 | 870 |
51. If the average number of mobiles sold by shops R, S, and T in 2021 is 800, then find the number of mobiles sold by shop T in 2021. (Data Sufficiency)
(a) 720
(b) 760
(c) 900
(d) 840
(e) None of these
Answer: (d) 840
Solution:
Average mobiles sold by R, S, T in $2021 = 800$
R ($2021$) = $600$, S ($2021$) = $960$, T = ?
$$ \frac{600 + 960 + T}{3} = 800$$
$$ \rightarrow 1560 + T = 2400$$ $$ \rightarrow T = 840$$
52. Find the ratio of the number of mobiles sold by shop R in 2021 to the number of mobiles sold by shop S in 2022. (Data Sufficiency)
(a) 20 : 29
(b) 13 : 15
(c) 18 : 17
(d) 17 : 19
(e) None of these
Answer: (a) 20 : 29
Solution:
Required ratio = $$600 : 870 = \frac{60}{87} $$
$$= \frac{20}{29}$$
$$= 20:29$$
53. Find the difference between the number of mobiles sold by shop P and Q together in 2021 and the number of mobiles sold by shop R and S together in 2022. (Data Sufficiency)
(a) 320
(b) 290
(c) 220
(d) 170
(e) None of these
Answer: (b) 290
Solution:
Total mobiles sold by $P$ and $Q$ in $2021$ = $540 + 840 = 1380$
Total mobiles sold by $R$ and $S$ in $2022$ = $800 + 870 = 1670$
Hence, required difference $1670 – 1380 = 290$
54. Out of the total number of mobiles sold by shop S in 2021, 30% of the mobiles sold were of A brand and the remaining mobiles were of B brand. Find the difference between the number of A and B brand mobiles sold by shop S in 2021. (Data Sufficiency)
(a) 328
(b) 384
(c) 360
(d) 352
(e) None of these
Answer: (b) 384
Solution:
S (2021) = 960
- A brand = 30% of 960 = $0.3 \times 960 = 288$
- B brand = $960 – 288 = 672$
Difference $= 672 – 288 = 384$
55. The number of mobiles sold by shop Q and R together in 2021 is what percentage of the number of mobiles sold by shop R in 2022? (Data Sufficiency)
(a) 125%
(b) 150%
(c) 180%
(d) 100%
(e) None of these
Answer: (c) 180%
Solution:
Total mobiles sold by shops $Q$ and $R$ in $2021 = 840 + 600 = 1440$
Mobiles sold by shop $R$ in $2022 = 800$
Hence, required percentage $$= \frac{1440}{800} \times 100 = 180%$$
56. Sanjay invested ₹ 9000 in compound interest at R% per annum for 2 years and obtained an interest of ₹ 3960. If he invested the same amount in simple interest at (R + 5)% per annum for 3 years, then find the simple interest received by Sanjay. (Simple & Compound Interest)
(a) ₹ 2100
(b) ₹ 3500
(c) ₹ 4050
(d) ₹ 2025
(e) None of these
Answer: (e) None of these
Solution:
Given: Compound Interest on ₹9000 for 2 years = ₹3960
Amount after 2 years: $A = 9000 + 3960 = 12960$
Using compound interest formula:
$$12960 = 9000\left(1 + \frac{R}{100}\right)^2$$
$$\left(1 + \frac{R}{100}\right)^2 = \frac{12960}{9000} = 1.44$$
$$1 + \frac{R}{100} = \sqrt{1.44} = 1.2 \Rightarrow R = 20\%$$
Now, Simple Interest at $(20 + 5)\% = 25\%$ for 3 years:
$$SI = \frac{9000 \cdot 25 \cdot 3}{100} = 6750$$
57. The selling price of the shirt, when marked up by 40% and then sold at 25% discount is equal to the selling price of the same shirt when marked up by 50% and then sold with a discount of ₹ 180. Find the selling price of the shirt if it is to be sold at 25% profit. (Profit &Loss)
(a) ₹ 260
(b) ₹ 520
(c) ₹ 500
(d) ₹ 650
(e) None of these
Answer: (c) ₹ 500
Solution:
Let the cost price be $x$.
Marked up by 40%, then 25% discount:
$$ \text{Selling Price}_1 = 1.4x \times (1 – 0.25) = 1.4x \times 0.75 = 1.05x $$
Marked up by 50%, then ₹180 discount:
$$ \text{Selling Price}_2 = 1.5x – 180$$
Given both selling prices are equal:
$$ 1.05x = 1.5x – 180 $$
Solving:
$$ 1.5x – 1.05x = 180 \Rightarrow 0.45x = 180 \Rightarrow x = \frac{180}{0.45} = 400$$
Selling price at 25% profit:
$$ \text{Selling Price} = 1.25 \times 400 = 500$$
58. P starts a business with an investment of ₹ 40,000. After 6 months Q joins with a certain investment. At the end of one year, the profit share of Q is ₹ 10,500 out of the total profit of ₹ 24,500. Find the investment of Q. (Profit &Loss)
(a) ₹ 80000
(b) ₹ 50000
(c) ₹ 60000
(d) ₹ 70000
(e) ₹ 75000
Answer: (c) ₹ 60000
Solution:
P’s investment for 12 months:
$$ 40000 \times 12 = 480000$$
Let Q’s investment be $x$ for 6 months:
$$\text{Q’s Capital} = x \times 6 = 6x$$
Ratio of P:Q = $480000 : 6x = \frac{80000}{x}$
Q’s share of total profit ₹24500 is ₹10500:
$$\frac{x}{80000 + x} \times 24500 = 10500$$
Cross-multiplying:
$$24500x = 10500(80000 + x)$$
$$24500x = 840000000 + 10500x$$ $$14000x = 840000000 \Rightarrow x = \frac{840000000}{14000} = 60000$$
59. A boat covers 27 km upstream in 3 hours and the boat covers 48 km downstream in 4 hours. Find the ratio of the speed of the boat in still water to the speed of the stream. (Boat & Streams)
(a) 5 : 2
(b) 7 : 3
(c) 4 : 3
(d) 9 : 5
(e) 7 : 1
Answer: (e) 7 : 1
Solution:
Upstream speed: $\frac{27}{3} = 9 \text{ km/h}$
Downstream speed: $\frac{48}{4} = 12 \text{ km/h}$
Let speed of boat in still water be $b$ and speed of stream be $s$.
Then: $b + s = 12,\quad b – s = 9$
Adding: $ 2b = 21 \Rightarrow b = 10.5$
Then: $s = 12 – 10.5 = 1.5$
Ratio of speed of boat in still water to speed of stream: $ \frac{b}{s} = \frac{10.5}{1.5} = 7:1$
60. The average age of five friends is 84 years. If one new friend is added, then the average decreases by 4 years. Find the age of the new friend. (Ages)
(a) 30 years
(b) 42 years
(c) 60 years
(d) 36 years
(e) 55 years
Answer: (c) 60 years
Solution:
Average age of 5 friends = 84
Total age = $84 \times 5 = 420$
New average after adding one person = $84 – 4 = 80$
Total age of 6 people = $80 \times 6 = 480$
Age of new friend: $480 – 420 = 6$$
61. The side of the square is 12 cm less than the sum of the length and the breadth of the rectangle and the breadth of the rectangle is 10 cm. If the perimeter of the square is 18 cm more than that of the rectangle, then find the length of the rectangle. (Mensuration)
(a) 24 cm
(b) 18 cm
(c) 15 cm
(d) 20 cm
(e) 23 cm
Answer: (e) 23 cm
Solution:
Let the length of the rectangle be $x$ cm.
Breadth of rectangle = 10 cm
So, sum of length and breadth = $x + 10$
Side of the square = $x + 10 – 12 = x – 2$
Perimeter of rectangle = $2(x + 10)$
Perimeter of square = $4(x – 2)$
Given: Perimeter of square is 18 cm more than that of rectangle
$$4(x – 2) = 2(x + 10) + 18$$
Expanding both sides:
$$4x – 8 = 2x + 20 + 18 \Rightarrow 4x – 8 = 2x + 38$$ $$4x – 2x = 38 + 8 \Rightarrow 2x = 46 \Rightarrow x = 23$$
DIRECTIONS (Qs. 62–66): Find out the wrong number in the following number series.
62. 590, 302, 159, 86, 50, 32, 23 (Number Series)
(a) 50
(b) 32
(c) 302
(d) 159
(e) 86
Answer: (d) 159
Solution:
Given number series:
$$590,\ 302,\ 159,\ 86,\ 50,\ 32,\ 23$$
Find the differences between consecutive terms:
$$590 – 302 = 288$$
$$302 – 159 = 143$$
$$159 – 86 = 73$$
$$86 – 50 = 36$$
$$50 – 32 = 18$$
$$32 – 23 = 9$$
Now observe the pattern of differences:
$$288,\ 143,\ 73,\ 36,\ 18,\ 9$$
Each number is approximately half of the previous:
$$288 \div 2 = 144$$
$$144 \div 2 = 72$$
$$72 \div 2 = 36$$
$$36 \div 2 = 18$$
$$18 \div 2 = 9$$
But:
$$302 – 144 = 158\ (\text{expected value})$$
Given value is $159$, which breaks the pattern.
Wrong number = 159
63. 21.5, 26, 29.5, 35, 41.5, 49 (Number Series)
(a) 41.5
(b) 49
(c) 26
(d) 35
(e) 29.5
Answer: (c) 26
Solution:
Given number series: $21.5,\ 26,\ 29.5,\ 35,\ 41.5,\ 49$
Find the differences between consecutive terms:
$$26 – 21.5 = 4.5$$
$$29.5 – 26 = 3.5$$
$$35 – 29.5 = 5.5$$
$$41.5 – 35 = 6.5$$
$$49 – 41.5 = 7.5$$
So, the differences are:
$$4.5,\ 3.5,\ 5.5,\ 6.5,\ 7.5$$
Clearly, 3.5 breaks the increasing pattern.
The correct difference should be $$5.5$$ after 4.5.
So, the wrong number in the series is $$26$$
64. 180, 268, 234, 316, 226, 364 (Number Series)
(a) 364
(b) 268
(c) 234
(d) 276
(e) 316
Answer: (c) 234
Solution:
Series: 180, 268, 234, 316, 226, 364
Differences:
$$+88,\ -34,\ +82,\ -90,\ +138$$
The alternating pattern of increasing and decreasing breaks at 234.
Correct pattern resumes if 234 is replaced.
65. 160, 329, 554, 825, 1204, 1645 (Number Series)
(a) 329
(b) 1204
(c) 1645
(d) 825
(e) 554
Answer: (d) 825
Solution:
Given series:
$$160,\ 329,\ 554,\ 825,\ 1204,\ 1645$$
Find differences:
$$329 – 160 = 169 = 13^2$$
$$554 – 329 = 225 = 15^2$$
$$825 – 554 = 271 \quad \text{(Not a perfect square)}$$
$$1204 – 825 = 379 \quad \text{(Not a perfect square)}$$
$$1645 – 1204 = 441 = 21^2$$
Expected pattern in differences:
$$13^2,\ 15^2,\ 17^2,\ 19^2,\ 21^2 = 169,\ 225,\ 289,\ 361,\ 441$$
So, after 554, next number should be:
$$554 + 289 = 843$$
But given is $825$ ⇒ Incorrect
Wrong number = 825
66. 250, 242, 230, 218, 198, 170 (Number Series)
(a) 198
(b) 230
(c) 218
(d) 242
(e) 170
Answer: (b) 230
Solution:
Given series:
$$250,\ 242,\ 230,\ 218,\ 198,\ 170$$
Find the differences between consecutive terms:
$$242 – 250 = -8$$
$$230 – 242 = -12$$
$$218 – 230 = -12$$
$$198 – 218 = -20$$
$$170 – 198 = -28$$
The differences are:
$$-8,\ -12,\ -12,\ -20,\ -28$$
Check pattern:
If the differences decrease by 8 each time:
$$-8,\ -16,\ -24,\ -32,\dots$$
Now apply this pattern starting from 250:
$$250 – 8 = 242$$
$$242 – 16 = 226$$
$$226 – 24 = 202$$
$$202 – 32 = 170$$
Expected series:
$$250,\ 242,\ 226,\ 202,\ 170$$
But the given series has 230 instead of 226 ⇒ 230 is incorrect
67. A male can do “w” work in 60 days and one female can do the same work in 50 days. In how many days 6 males and 5 females together can complete “3w” work? (Time & Work)
(a) 32 days
(b) 12 days
(c) 15 days
(d) 20 days
(e) None of these
Answer: (c) 15 days
Solution:
One male can do work $w$ in 60 days → rate = $\frac{w}{60}$
One female can do work $w$ in 50 days → rate = $\frac{w}{50}$
Combined rate of 6 males and 5 females: $6 \times \frac{w}{60} + 5 \times \frac{w}{50} = \frac{w}{10} + \frac{w}{10} = \frac{w}{5}$
To complete $3w$ work: $ \frac{3w}{\frac{w}{5}} = 15 \text{ days}$
68. The ratio of P’s age a years hence to Q’s age 6 years ago is 5 : 2 and the sum of the present ages of P and Q is 58 years. If the age of Q and R after 2a years is 62 years and the present age of R is 24 years, then find the present age of Q. (Ratio & Proportion)
(a) 20 years
(b) 22 years
(c) 24 years
(d) 36 years
(e) Cannot be determined
Answer: (b) 22 years
Solution:
Let present age of Q be $q$.
Given:
$$ q + 4a = 38,\quad \frac{58 – q + a}{q – 6} = \frac{5}{2}$$
From the first:
$$ a = \frac{38 – q}{4}$$
Substitute into second:
$$ \frac{58 – q + \frac{38 – q}{4}}{q – 6} = \frac{5}{2}$$
Simplifying:
$$\frac{4(58 – q) + (38 – q)}{4(q – 6)} = \frac{5}{2} \Rightarrow \frac{270 – 5q}{4(q – 6)} = \frac{5}{2}$$
Cross-multiplying:
$$2(270 – 5q) = 20(q – 6) \Rightarrow 540 – 10q = 20q – 120$$
$$660 = 30q \Rightarrow q = 22$$
69. J can complete the work in 20 days. If J started the work and after 4 days, K joined the work, then J and K together complete the remaining work in 8 days, then find the time taken by J and K together to complete the work. (Time & Work)
(a) 20 days
(b) 18 days
(c) 24 days
(d) 10 days
(e) 15 days
Answer: (d) 10 days
Solution:
J can complete the work in 20 days
In 4 days, J completes: $\frac{4}{20} = \frac{1}{5}$
Remaining work = $\frac{4}{5}$, done by J and K together in 8 days
Combined rate: $\frac{4}{5} \div 8 = \frac{1}{10}$
J’s rate = $\frac{1}{20}$
K’s rate = $\frac{1}{10} – \frac{1}{20} = \frac{1}{20}$
Together, they complete: $$\frac{1}{20} + \frac{1}{20} = \frac{1}{10} \Rightarrow \text{Time} = 10 \text{ days}$$
70. A train length 240 m crosses a 360 m platform in 40 seconds. If the train running at 33.33% less than its usual speed, then find the time taken by the train to cross a pole. (Time & Distance)
(a) 29 seconds
(b) 24 seconds
(c) 35 seconds
(d) 27 seconds
(e) 30 seconds
Answer: (b) 24 seconds
Solution:
Train length = 240 m, Platform length = 360 m
Total distance = $240 + 360 = 600$ m
Time = 40 seconds
Speed of train: $\frac{600}{40} = 15 \text{ m/s}$
Reduced speed = $15 \times \left(1 – \frac{1}{3}\right) = 15 \times \frac{2}{3} = 10$ m/s
Time to cross a pole: $\frac{240}{10} = 24 \text{ seconds}$
Section 3 : English Language
| English Language | No. of Questions |
| Passage | 9 |
| Para Jumbles | 5 |
| Word Swap | 5 |
| Sentence Rearrangement (Jumbled Sentence Parts) | 5 |
| Finding Errors | 3 |
| Vocabulary | 3 |
| Total | 30 |
DIRECTIONS (Qs. 71-79): Read the given passage and answer the following questions. Some parts have been highlighted to aid in answering the questions.
Maya skipped excitedly into her grandma’s cozy kitchen. The aroma of freshly baked cookies hung in the air, making her stomach rumble. Grandma, wearing her signature flour-dusted apron, smiled warmly.
“Maya, my dear, just in time! I need your help decorating these chocolate chip cookies.” Maya’s heart sank. Decorating meant sprinkles, and sprinkles always ended up in her hair, much to her mother’s dismay.
“But Grandma,” she pleaded, “can’t we just eat them plain this time?” Grandma chuckled, her eyes twinkling. “Not these, Maya. These are special cookies for the annual bake sale at the community center tomorrow.”
Disappointment clouded Maya’s face. Bake sale cookies meant no afternoon snack. Grandma, sensing her granddaughter’s dejection, winked. “Tell you what,” she said, “after we decorate, I’ll let you choose one small, unfrosted cookie as a reward.”
Maya’s spirits lifted. A plain cookie was better than none at all.
The next morning, Maya woke up feeling famished. She raced to the kitchen, hoping to snag a sneak peek of the decorated cookies. But to her surprise, the plate was empty! Panic seized her. “Grandma!” she cried, rushing into the living room. “The cookies are gone!”
Grandma, reading the newspaper, looked up calmly. “Don’t worry, Maya. I took them to the bake sale early this morning.” Relief washed over Maya. But then, a new thought struck her. “Wait, Grandma,” she said, eyes widening, “what about my reward cookie?”
Grandma’s smile faltered for a moment. “Oh, dear,” she mumbled, “it seems I might have…forgotten it at home.” Maya’s stomach twisted. No cookie? After all that anticipation?
Suddenly, a mischievous glint appeared in Grandma’s eyes. “But,” she continued, “I do have an idea. There’s a secret hiding place in the kitchen where I keep some extra treats. Can you find it, detective Maya?”
With renewed enthusiasm, Maya embarked on a treasure hunt, searching every nook and cranny of the kitchen. Finally, she spotted a loose floorboard behind the pantry. Prying it open, she discovered a small, dusty box. Inside, nestled amongst old recipe cards, lay a single, unfrosted chocolate chip cookie.
Maya grinned triumphantly. While the hunt wasn’t exactly what she had expected, it had been an adventure. And besides, the reward cookie tasted even sweeter after all the effort.
71. What was Maya initially disappointed about? (Passage)
(a) Having to decorate the cookies
(b) Not being allowed to eat any cookies
(c) The smell of freshly baked cookies
(d) Not being able to help her grandma
(e) For spotting a loose floorboard
Answer: (a) Having to decorate the cookies
Solution: Maya’s heart sank when she realized she had to decorate the cookies with sprinkles.
72. What did Grandma offer Maya as a compromise? (Passage)
(a) To help her decorate the cookies
(b) To let her choose one frosted cookie
(c) To bake her a separate batch of plain cookies
(d) To let her choose one unfrosted cookie
(e) To bake some special cookies for her
Answer: (d) To let her choose one unfrosted cookie
Solution: Grandma said, “I’ll let you choose one small, unfrosted cookie as a reward.”
73. Why was the plate empty the following morning? (Passage)
(a) Maya had eaten all the cookies by herself.
(b) Grandma had forgotten the cookies at home.
(c) Grandma had taken the cookies to the bake sale.
(d) Someone had stolen the cookies.
(e) The cookies had been thrown away.
Answer: (c) Grandma had taken the cookies to the bake sale.
Solution: Grandma calmly told Maya she had taken them early that morning.
74. What was Grandma’s initial reaction when Maya asked about her reward cookie? (Passage)
(a) She was angry that Maya had forgotten about it.
(b) She apologized for forgetting it at home.
(c) She offered to bake Maya another cookie.
(d) She pretended not to remember the promise.
(e) She was surprised when Maya asked about the reward cookie.
Answer: (b) She apologized for forgetting it at home.
Solution: Grandma said, “Oh, dear, it seems I might have…forgotten it at home.”
75. How did Maya find the reward cookie? (Passage)
(a) Grandma gave it to her directly.
(b) Maya found it hidden in the pantry.
(c) Maya won it in a game with Grandma.
(d) Maya found it in a secret hiding place.
(e) She found the cookie in her room.
Answer: (d) Maya found it in a secret hiding place.
Solution: She discovered a loose floorboard behind the pantry with a small box inside.
76. What is the main lesson Maya learns in this story? (Passage)
(a) The importance of following instructions exactly.
(b) The value of relationships.
(c) The importance of being patient and understanding.
(d) The joy of solving a mystery.
(e) The value of hard work and perseverance.
Answer: (e) The value of hard work and perseverance.
Solution: Maya searched the kitchen and found the reward cookie through effort.
77. What is the tone of the passage? (Passage)
(a) Serious and suspenseful
(b) Light-hearted and playful
(c) Informative and educational
(d) Dark and mysterious
(e) Playful and mocking
Answer: (b) Light-hearted and playful
Solution: The story is warm and whimsical, filled with gentle humor and curiosity.
78. What can you infer about Grandma’s character from the story? (Passage)
(a) She is strict and expects Maya to always obey her.
(b) She is forgetful and sometimes makes mistakes.
(c) She is creative and enjoys playing games with Maya.
(d) She is selfish.
(e) She is headstrong and manipulative.
Answer: (c) She is creative and enjoys playing games with Maya.
Solution: Grandma turned the disappointment into a fun treasure hunt.
79. What detail from the passage foreshadows that Maya might not get her reward cookie? (Passage)
(a) Maya’s initial disappointment about decorating the cookies.
(b) Grandma taking the cookies to the bake sale early in the morning.
(c) Grandma’s offer to let Maya choose an unfrosted cookie.
(d) The description of the secret hiding place for treats.
(e) Maya’s excitement about the smell of freshly baked cookies.
Answer: (b) Grandma taking the cookies to the bake sale early in the morning.
Solution: This action hinted that she may have taken all cookies, including Maya’s reward.
DIRECTIONS (Qs. 80–84): Rearrange the following sentences in the proper sequence to form a meaningful paragraph and answer the questions given below them.
80. Five sentences are given below, labeled A, B, C, D, and E. They need to be arranged in a logical order to form a coherent paragraph/passage. From the given options, choose the most appropriate option. (Para Jumbles)
A. The species, which are most numerous in individuals, will have the best chance of producing variations within any given period.
B. Hence any rare species will be less quickly modified or improved within any given period, and they will be consequently beaten in the race for life by the modified descendants of the commoner species.
C. From these considerations, I think it inevitably follows, that as new species in the course of time are formed, others will become rare and finally extinct.
D. We have evidence of this in the fact that it is the more common species that afford the greatest number of varieties, or incipient species.
E. Extinction or survival, therefore, is a function of a parameter that is totally beyond the control of the species.
(a) ABCDE
(b) ADBCE
(c) BCAED
(d) EDABC
Answer: (b) ADBCE
Solution:
A introduces the idea of more numerous species producing more variations.
D supports A with evidence.
B follows with a conclusion about rare species being outcompeted.
C generalizes this idea to extinction.
E sums it up philosophically
81. (Para Jumbles)
A. The chief modern challenge to myth has come not from ethics but from science.
B. Where Plato bemoans myths for presenting the gods as practitioners of immoral behavior, modern critics dismiss myth for explaining the world unscientifically.
C. It was above all the Stoics who defended myth against this charge by reinterpreting it allegorically.
D. In the West, the challenge to myth goes back at least to Plato, who rejected Homeric myth on, especially, ethical grounds.
E. Here myth is assumed to explain how gods control the physical world rather than, as for Plato, how they behave among themselves.
(a) ABCDE
(b) AEDCB
(c) DCAEB
(d) BDCAE
Answer: (c) DCAEB
Solution:
D introduces the historical challenge to myth.
C explains Stoic defense.
A brings in the modern perspective.
E contrasts the ancient and modern views.
B expands Plato’s criticism.
82. (Para Jumbles)
A. It also made clear that economic ideology in the service of capitalism does not need logic on its side!
B. The debate on capital theory was logically won with its devastating implications for standard theory, and yet nothing changed in the profession!
C. In this demolition job of neoclassical capital theory, Joan Robinson again became a main player, and popularised its implications for economic theory through her writings.
D. In disgust, Joan Robinson picked up the word “mumpsimus,” which means a traditional notion that is obstinately held although it is unreasonable.
E. Business continued as usual, because the vested intellectual interest in standard neoclassical economics as a worldwide industry was too great.
(a) BEADC
(b) CBEAD
(c) ADBEC
(d) BECDA
Answer: (b) CBEAD
Solution:
C introduces Robinson’s role.
B explains the outcome of the debate.
E shows the profession’s resistance.
A gives an insight into ideology.
D adds Robinson’s reaction.
83. (Para Jumbles)
A. If at one time, one knew the positions and velocities of all the particles in the universe, the laws of science should enable us to calculate their positions and velocities at any other time, past or future.
B. These laws may or may not have been ordained by God, but scientific determinism asserts that he does not intervene to break them.
C. But it was Newton’s Principia Mathematica in 1687, containing his theory of universal gravitation that made the laws quantitative and precise.
D. A qualitative understanding of the laws has been the aim of philosophers and scientists, from Aristotle onwards.
E. This led to the idea of scientific determinism, which seems first to have been expressed by Laplace.
(a) DCABE
(b) DCEAB
(c) ADCEB
(d) EBDCA
Answer: (b) DCEAB
Solution: (D-C) can be seen to be the opening pair in this parajumble as it sets the context for the entire discussion. This effectively leads us to choose between options (a) and (b). Option (a) can be eliminated as statement B can come only after statement E. Statement E introduces the idea of scientific determinism.
84. (Para Jumbles)
A. Classical music, by contrast, encodes maturity and, by extension, the demands of responsibility to family and to society.
B. The meaning of the commercial emerges out of this odd juxtaposition of the music you see and the music you hear.
C. What the commercial is saying (though not in so many words, of course) is that you can begin responsible financial planning without selling out on your youth, freedom, and spontaneity.
D. Rock stands for youth, freedom, being true to yourself; in a word, authenticity.
E. Through music, the commercial accomplishes a kind of conjuring trick, combining both sets of values and in this way selling the advertiser’s message (you need to start planning for your old age now) to a segment of society that might be expected to be resistant to it.
(a) BDAEC
(b) EDABC
(c) ECBDA
(d) BECDA
Answer: (a) BDAEC
Solution:
B is the opening sentence as it introduces the topic, The word this’ in B is a demonstrative adjective and describes the juxtaposition. D and A continue this idea and explain by giving examples of rock and classical music. DA forms a mandatory pair as A talks about the condensed and elaborate meanings of classical music. E should come immediately after DA as it talks about both sets of values. C summaries the whole concept and should come in the end. EC forms a mandatory pair as both the sentences talk about commercials depicting an idea through music.
DIRECTIONS (Qs. 85–89): In each of the questions given below, four words are given in bold. These four words may or may not be in their correct position. The sentence is then followed by an option with the correct combination of words that should replace each other in order to make the sentence grammatically and contextually correct. Find the correct combination of the words that replace each other. If the sentence is correct as it is, then select option (e) as your choice.
85. The warm (A) set behind the valley (B), casting a sun (C) glow over the mountains (D). (Word Swap)
(a) A–D
(b) A–B
(c) C–D
(d) A–C, B–D
(e) No interchange needed
Answer: (d) A–C, B–D
Solution:
Correct sentence: The sun set behind the mountains, casting a warm glow over the valley.
86. As she entered the room (A), she noticed a small (B) spider dangling (C) from the ceiling (D). (Word Swap)
(a) A–D
(b) A–B, C–D
(c) B–C
(d) A–C, B–D
(e) No interchange needed
Answer: (e) No interchange needed
Solution:
Correct sentence: As she entered the room, she noticed a small spider dangling from the ceiling.
Nothing needs to be changed
87. The shade (A) oak tree provided old (B) from the hot (C) summer sun (D). (Word Swap)
(a) A–C, B–D
(b) A–B
(c) A–D, B–C
(d) C–D
(e) No interchange needed
Answer: (b) A–B
Solution:
shade and old are misplaced, swapping them fixes the meaning
Correct sentence: The old oak tree provided shade from the hot summer sun.
88. His exotic (A) job required him (B) to travel (C) frequently to new (D) locations. (Word Swap)
(a) B–C, A–D
(b) A–B, C–D
(c) A–D
(d) B–C
(e) No interchange needed
Answer: (c) A–D
Solution: swap A (exotic) and D (new)
Correct sentence: His new job required him to travel frequently to exotic locations.
89. The rich (A) ruins stood as a testament (B) to the ancient (C) history of the region (D). (Word Swap)
(a) A–C
(b) B–D
(c) A–B
(d) C–D
(e) No interchange needed
Answer: (a) A–C
Solution: Swap A (rich) and C (ancient) to get: ancient ruins and rich history
Correct sentence: The ancient ruins stood as a testament to the rich history of the region
DIRECTIONS (Qs. 90–94): Each of the following questions gives a sentence which has been divided into four parts which might not be in their correct order of narrative. The sentence is then followed by five options, one of which gives the sequence of the rearranged parts to make the sentence meaningful. You must choose the option which gives the correct sequence of parts. If the sentence is already arranged in the correct sequence or the correct sequence does not match with any of the given sentence, make option(e) ‘No rearrangement required’ as your answer.
90. Farm workers (P)/ spend (Q)/ outdoors (R)/ most of their time (S). (Jumbled Sentence Parts)
The proper sequence should be:
(a) PRQS
(b) PRQS
(c) PQSR
(d) RPQS
(e) SQRQ
Answer: (c) PQSR
Solution: Farm workers spend most of their time outdoors.
91. He (P)/ shuffled the papers (Q)/ in a drawer (R)/ together (S). (Jumbled Sentence Parts)
The proper sequence should be:
(a) PQSR
(b) PRQS
(c) QRPS
(d) QPRS
(e) PRSQ
Answer: (a) PQSR
Solution: He shuffled the papers together in a drawer.
92. Do you think (P)/ will (Q)/ this soap (R)/ shrink woollen clothes? (S). (Jumbled Sentence Parts)
The proper sequence should be:
(a) PQRS
(b) PRQS
(c) QRPS
(d) QPRS
(e) PRSQ
Answer: (b) PRQS
Solution: Do you think this soap will shrink woollen clothes?
93. We advised (P)/ the hijackers to surrender (Q)/ to the police (R)/ themselves (S). (Jumbled Sentence Parts)
The proper sequence should be:
(a) PQRS
(b) PRQS
(c) PQSR
(d) RPQS
(e) RQPS
Answer: (c) PQSR
Solution: We advised the hijackers to surrender themselves to the police.
94. Sports car (P)/ appeal (Q)/ to some motorists only (R)/ with noisy exhausts (S). (Jumbled Sentence Parts)
The proper sequence should be:
(a) RQSP
(b) PSQR
(c) RSPQ
(d) PQSR
(e) RPQS
Answer: (b) PSQR
Solution: Sports car with noisy exhausts appeal to some motorists only.
DIRECTIONS (Qs. 95–97): The sentences given below are divided into four parts. Identify the segment that contains an error in it. If there is no error, then choose (e) ‘No error’. (Finding Errors)
95. Nuclear waste will still being (a)/ radioactive even after twenty thousand years, (b)/ so it must be disposed (c)/ of very carefully. (d)/ No error (e)
Answer: (a)
Solution:
will still being → incorrect
Corrected Sentence: Nuclear waste will still be radioactive even after twenty thousand years, so it must be disposed of very carefully
96. My friend lived at the top (a)/ of an old house (b)/ which attic had been (c)/ converted into a flat. (d)/ No error (e)
Answer: (c)
Solution: The phrase “which attic had been” is incorrect.
Corrected Sentence: My friend lived at the top of an old house whose attic had been converted into a flat.
97. A public safety advertising (a)/ campaign in Russia (b)/ hope to draw attention (c)/ of pedestrians crossing the road. (d)/ No error (e)
Answer: (c)
Solution: verb should be “hopes”, not “hope”.
Corrected Sentence: A public safety advertising campaign in Russia hopes to draw attention of pedestrians crossing the road.
DIRECTIONS (Qs. 98–100): Fill in the blanks using the correct word from the blank.
98. The poet’s __________ language captivated the audience, leaving them spellbound. (vocabulary)
(a) mundane
(b) conspicuous
(c) banal
(d) prosaic
(e) eloquent
Answer: (e) eloquent
Solution: “Eloquent language” is powerful, moving, and beautiful — exactly the kind of language that would captivate an audience and leave them spellbound.
99. The scientist’s __________ discovery revolutionized the field of genetics. (vocabulary)
(a) inconsequential
(b) seminal
(c) trivial
(d) peripheral
(e) resolute
Answer: (b) seminal
Solution: The discovery changed genetics in a big way. So, the word should mean very important.
“Seminal” means very important.
100. Despite facing numerous __________, she remained resilient and determined to achieve her goals. (vocabulary)
(a) hindrances
(b) advantages
(c) accolades
(d) encomiums
(e) reservations
Answer: (a) hindrances
Solution: She faced many problems but stayed strong. So, the word should mean problems or difficulties.
“Hindrances” means problems.