Explanation:
To solve this problem, we need to find all valid combinations of three-digit numbers using the digits 1 to 9, arranged in three rows. The number in the second row should be twice the number in the first row, and the number in the third row should be three times the number in the first row. Digits are not repeated, and only three of the four digits $2, 3, 7,$ and $9$ are allowed to be used in the first row.
Step-by-Step Solution:
1. Understanding the Problem:
– We need to form three numbers using the digits 1 to 9.
– The first number (formed by the first row) is $ABC$.
– The second number (formed by the second row) is $DEF = 2 \times ABC$.
– The third number (formed by the third row) is $GHI = 3 \times ABC$.
– No digits are repeated among $A, B, C, D, E, F, G, H,$ and $I$.
– Only three digits out of $2, 3, 7,$ and $9$ are allowed in the first row.
2. Determine the Possible Numbers in the First Row:
– Possible numbers formed using three digits from $2, 3, 7,$ and $9$ without repetition:
– The potential numbers are: $237, 239, 273, 279, 297, 327, 329, 372, 379, 392, 723, 729, 732, 739, 792, 923, 927, 932, 937, 972$.
3. Checking Valid Combinations:
– We need to verify which of these numbers, when doubled and tripled, result in valid three-digit numbers with unique digits from 1 to 9.
Check Each Valid Combination:
– Combination: $297$
– First row: $297$
– Second row: $2 \times 297 = 594$
– Third row: $3 \times 297 = 891$
– Digits used: $2, 9, 7, 5, 4, 8, 1, 3, 6$ (All unique and cover 1-9 exactly)
This combination satisfies all the conditions.
– Combination: $327$
– First row: $327$
– Second row: $2 \times 327 = 654$
– Third row: $3 \times 327 = 981$
– Digits used: $3, 2, 7, 6, 5, 4, 9, 8, 1$ (All unique and cover 1-9 exactly)
This combination satisfies all the conditions.
– Combination: $392$
– First row: $392$
– Second row: $2 \times 392 = 784$
– Third row: $3 \times 392 = 1176$
– Digits used: $3, 9, 2, 7, 8, 4, 1, 1, 6$ (Digits are repeated)
This combination does not satisfy the conditions because it repeats digits.
Summary of Valid Combinations:
– $297, 594, 891$
– $327, 654, 981$
There are two valid combinations.
Conclusion:
The correct answer is (c) 2.